An 80kg woman jumps from a wall and lands stiff legged in...

An 80 kg woman jumps from a wall and lands stiff-legged in soft sand. The woman's downward speed just as she touches the sand is 6 m/s. She is stopped after sinking 0.05 m into the sand. Calculate the net force on the woman while she is being stopped by the sand.

Transcript

00:01 In this question we have given the identical 6 identical blocks whose weight are 100 newton and are placed on a level table we have to find the supporting force on the block in each case so i am first i'm taking the first case that is for a we have given the block here and the weight of this block is that is 100 newton which is acting vertically downed that is 100 newton and we had applied a force on this block that is f is equal to this is 50 newton and the supporting force on this block is the force due to the ground that is fn which is acting vertically upward so we have to calculate this fn force so we can say that acceleration in y direction is zero so we can say that net force in wide direction is equal to zero so we can say that this f plus fn should equals to the hundred newton so from here we get the value of fn that is hundred minus 50 that is equal to 15 newton so this is the supporting force for the first block and this is our answer for the first part of the problem now in similarly we can find for the second case that is b now in the second case we have given this block and now the force is applied on the object that is f is equal to f 50 newton this is the pushing force and weight of this block is acting vertically download that is 100 newton now the let the supporting force between the block and the table is fn which is acting vertically downward.

01:45 Similarly we can say that the net force that is fn in upward direction should be equal to net downward force that is 50 plus 100 so we can say this will comes out to be 150 newton.

01:59 So this is the answer of our second part of the problem or we can support second block.

02:08 Now we can find for third block so we can say that this is the condition given to us, that is, we applied a force in horizontal direction that is f is equal to 50 newton.

02:22 So we can say that weight of this block is acting vertically downwood that is 100 newtom and the supporting force, that is fn is vertically upward.

02:29 As we can say that there is no motion in the vertical direction...

Question

An 80 kg woman jumps from a wall and lands stiff-legged in soft sand. The woman's downward speed just as she touches the sand is 6 m/s. She is stopped after sinking 0.05 m into the sand. Calculate the net force on the woman while she is being stopped by the sand.

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