5 \, \text{Hz} \)
- \( L = 28.5 \, \text{mH} = 28.5 \times 10^{-3} \, \text{H} \)
Now, substituting the values:
\[ X_L = 2\pi (78.5) (28.5 \times 10^{-3}) \]
\[ X_L \approx 2\pi (78.5) (0.0285) \]
\[ X_L \approx 2\pi (2.23725) \]
\[ X_L \approx 14.05
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