an accepted relationship between stoppin distance is d(v)=1.3v+0.04v^(2) how many many feet will it take a car traveling 40mph to sto
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The stopping distance, d ( in feet) for a car moving at a velocity (speed) v miles per hour is modeled by the equation: d = 0.04 v squared + 1.1 v What is the stopping distance for a velocity of 40 miles per hour? a. 108 ft c. 120 ft b. 72 ft d. 138 ft
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An accepted relationship between stopping distance, d in feet, and the speed of a car, v in mph, is d(v) = 1.2v + 0.05v^2 on dry, level concrete. (a) How many feet will it take a car traveling 40 mph to stop on dry, level concrete? (b) If an accident occurs 250 feet ahead, what is the maximum speed at which one can travel to avoid being involved in the accident? (a) It will take ft to stop the car that is traveling at 40 mph. (Round up to the nearest foot as needed.) (b) The maximum speed is mph at which one can travel to avoid being involved in the accident. (Round down to the nearest mile per hour as needed.)
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An accepted relationship between stopping distance, d in feet, and the speed of a car, v in mph, is d(v) = 1.2v + 0.04v^2 on dry, level concrete. (a) How many feet will it take a car traveling 45 mph to stop on dry, level concrete? (b) If an accident occurs 150 feet ahead, what is the maximum speed at which one can travel to avoid being involved in the accident? (a) It will take 135 ft to stop the car that is traveling at 45 mph. (Round up to the nearest foot as needed.) (b) The maximum speed is mph at which one can travel to avoid being involved in the accident. (Round down to the nearest mile per hour as needed.)
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