00:01
I'm not going to write down the table.
00:01
I'm just going to look at the results on my own screen.
00:04
But we want to find first of all the probability that a random student chosen is having tutor b.
00:11
And we know we have a total of 250 students.
00:14
And the number of those that had tutor b was 145.
00:17
And i'll leave you to make that a decimal.
00:20
Now on number two, we want to find the likelihood that someone had tutor b and at least passed.
00:26
Now there are 250 students.
00:28
And this is the intersection.
00:30
And so this would include everybody i believe.
00:34
Credit i assume is passing.
00:37
So if we take the 145 and subtract 12, and those are the ones that failed, that would be 133 out of 250.
00:46
And again, i'll leave that for you to get as a decimal.
00:50
Now we want the condition to be that the person is using the credit, no credit.
00:55
And we have 65 people.
00:57
We only care about that one column.
00:59
And how many of those have tutor b? that would be 39.
01:05
Now we want to know are these two b and highly distinctive, are they independent? well, one test is to find the probability of b, which is that 145.
01:19
And i guess i'll get that decimal for you right now.
01:24
And let me quit out of something i was on.
01:27
So that 145 divided by 250, that probability is .58.
01:37
And a couple ways we can do this.
01:40
But if we look at the likelihood of being highly distinctive, that is highly distinctive is 5 out of 250.
01:48
And 5 divided by 250 is going to end up giving us only .02.
01:53
And then we want to see what the probability of this and this is.
01:58
So that intersection.
01:59
And that is 4 out of 250.
02:04
And so 4 divided by 250 is .016.
02:10
Now if we take the product of these two, the .58 times .02, these need to be the same if we have independence.
02:19
And this product is .0116...