An aeroplane is diving at an angle of 20 degrees below the...

An aeroplane is diving at an angle of 20 degrees below the horizontal at a speed of 1000.00 km/h, when it drops a package. it takes the package 3.00 s to hit the ground after it was dropped. Ignore the effects of air resistance. Calculate: a.) At which height above the ground the package was dropped. b.) The horizontal distance the package moves when it is dropped, before hitting the ground. c.) The magnitude and direction of the velocity of the package just before it hits the ground.

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0:00 Hi.

00:01 Here in this given problem, this is the horizontal index line.

00:09 Then the direction of aeroplane, that direction in which aeroplane is flying, that is at an angle 20 degree below the horizontal.

00:21 It is flying with an initial velocity v -0 which is given as 1 ,000 .00 km per hour.

00:36 Is 1000 multiplied by 5 by 18 meter per second.

00:42 It is calculated to be equal to 277 .8 meter per second.

00:49 It takes a time, total time 3 .00 second to touch the ground.

01:03 The packet dropped from the airplane takes the time three second to touch the ground.

01:11 In the first part of the problem we have to find height of the aeroplane, the altitude where the aeroplane is flying.

01:23 For which first of all we dissolve this initial velocity into two components.

01:29 Horizontal component v -o -x, vertical component v -o -y.

01:36 So, using second equation of motion, h is equal to v -o -y -t plus half g -t -square.

01:51 Means this is v -o -sin -theta multiplied by t plus half g -t -square plugging in all the known values v o that is 277 .8 multiplied by sine 20 degree multiplied by 3 plus half times of 9 .8 multiplied by square of 3.

02:22 So this height is calculated to be equal to 3 29 .14 meter.

02:30 Answer for the first part of the problem.

02:33 This is the altitude at which the aeroplane is flying...

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