Question

An air-filled capacitor consists of two parallel plates, each with an area of 7.60 $\mathrm{cm}^{2}$ and separated by a distance of 1.80 $\mathrm{mm}$ . If a $20.0-\mathrm{V}$ potential difference is applied to these plates, calculate (a) the electric field between the plates, (b) the capacitance, and (c) the charge on each plate.

Name: An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm^2 and separated by a distance of 1.80 mm . If a 20.0-V potential difference is applied to these plates, calculate (a) the electric field between the plates, (b) the capacitance, and (c) the charge on each plate.
Uploaded: 2022-01-10T22:22:51-08:00
Duration: 2 min 42 s
Channel: Nishant Kumar
Description: An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm^2 and separated by a distance of 1.80 mm . If a 20.0-V potential difference is applied to these plates, calculate (a) the electric field between the plates, (b) the capacitance, and (c) the charge on each plate.

          An air-filled capacitor consists of two parallel plates, each with an area of 7.60 $\mathrm{cm}^{2}$ and separated by a distance of 1.80 $\mathrm{mm}$ . If a $20.0-\mathrm{V}$ potential difference is applied to these plates, calculate (a) the electric field between the plates, (b) the capacitance, and (c) the charge on each plate.

Added by Tom-S M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Nishant Kumar

01/10/2022

Step 1

Given: Potential difference, V = 20.0 V Separation between plates, d = 1.80 mm = 1.80 x 10^-3 m Electric field, E = V / d E = 20.0 V / 1.80 x 10^-3 m E = 1.11 x 10^4 V/m Show more…

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An air-filled capacitor consists of two parallel plates, each with an area of 7.60 $\mathrm{cm}^{2}$ and separated by a distance of 1.80 $\mathrm{mm}$ . If a $20.0-\mathrm{V}$ potential difference is applied to these plates, calculate (a) the electric field between the plates, (b) the capacitance, and (c) the charge on each plate.