85 \times 10^{-12} \, F/m$), $r_1$ is the inner-shell radius, and $r_2$ is the outer-shell radius.
Plugging in the given values, we get:
$C = 4 \pi (8.85 \times 10^{-12} \, F/m) \frac{(6.50 \times 10^{-2} \, m)(14.2 \times 10^{-2} \, m)}{(14.2 \times 10^{-2} \,
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