00:01
Hello everyone, in this question it is given that pressure at 0 .1 e1 equals to given 95 kilo pascal, temperature at 0 .1, e1 equals to given 300 kelvin, temperature at 0 .3 t3 equals to given, 1 ,800 kelvin, and mass m equals to given 0 .012 kg, and the ratio of v1 divided by v2 equals to given 15.
00:30
So now according to question, we can draw the pv diagram.
00:35
So this is our pv diagram according to question.
00:38
And now here at e1 equals to 300 kelvin from ideal property of air, we will get new 1 equals to 214 .07 kilojou per kg and the value of d suffix 01 equals to 6 .21.
01:03
So for iscentropic compression we can retain as f.
01:08
Suffix 1 divided by v.
01:09
Z suffix 2 equals to v suffix r1 divided by v suffix r2.
01:15
So from here we will get, and this is the value is vr1.
01:20
And therefore from here we will get 15 equals to 621 .2 divided by v suffix r2.
01:32
So therefore from here we will got the value of v suffix r2 equals to 41 .413.
01:40
So at b suffix r2 41 .40 we are using interpolation to find that temperature 2.
01:50
So now here we are using the interpolation method.
01:53
So therefore we will get 41 .413 minus 39 .12 divided by 41 .85 minus 39 .82 equals to t2 minus 860 divided by 840 minus 860 so therefore from here we will got the value of t2 equals to 843 .2 kelvin so now again we are interpreting for enthalpy so therefore from here we will get 41 .430 minus 39 .12 divided by 41 .85 minus 39 .12 equals to h2 minus 888 .27 divided by 866 .08 minus 888 .27.
03:01
So further solving this we will got the value of h2 equals to 869 .632 kilojou so now at tempestr tc equals to 80 ,000 kelvin, we will get the value h3 equals to 2 .0 c .c.
03:32
0 .0 .c.
03:33
K .g...