00:01
All right, so let's say we have two springs attached to a glider like this, and we're told that a force of half a newton is required to displace the glider a distance of 0 .17 meters.
00:15
So part a asks, what's the spring constant of the system? so this should, according to hooks law, just be the force divided by the displacement.
00:22
So 2 .94 newtons per meter.
00:26
We're told the gliders released.
00:28
We want to find the maximum acceleration of the glider.
00:31
So the mass of the glider, i should say, is 0 .95 kilograms.
00:36
So the acceleration, once again, through hooksaw, should be k -deltax over m, which is really like 0 .5 newtons over 0 .95 kilograms.
00:50
And so that comes out to 0 .53 meters per second squared...