00:01
For this problem to begin, we have a sample of size 80, with a sample mean value of being 10 minutes late, and a standard deviation of 12 minutes.
00:18
I'll note that since we have a very large sample, it doesn't actually matter that we only have a sample standard deviation.
00:23
We can still use the z distribution for constructing our confidence interval.
00:27
So we'll construct our 99 % confidence interval by taking our sample mean plus or minus the z score for a one -tail probability, 0 .005 times our sample standard deviation divided by the square root of our sample size, where that z score is going to be 2 .576.
00:55
So, calculating this out, we'll have a lower bound 12 minus 2 .576 times, or excuse, uh, actually, pardon me, our sample mean was 10 minutes late.
01:10
So it's 10 minus 2 .576 times, times 12 divided by the square root of 80 for the lower bound...