00:01
An airplane flies 200 kilometers due west from ccd8 to ccdb so i say this is ccdb is 200 kilometers and then 20k kilometers in the direction of 24 .5 degrees north of west sorry west be the other way around so that would be here which is b is a and then 24 .5 degrees north of west that is going north from west the angle will be here so to see to see this side is 280 kilometers one find in a short line distance how far i see to c from cta so let's find the y component of c of c of c this is 280 sine 24 .5 degrees then the x component is here 280 plus 24 .5 degrees.
01:26
So our submission, x, which is our total x component, it's going to be 280 minus 280 plus 24 .5, because that's the negative x direction, minus 200, that's also in negative x direction.
01:45
Then submission of y, this is just 280, sine 24 .5, this is in the positive y direction.
01:53
So this is equal to.
01:56
This is minus 454 .79 kilometers and this 116 .14 kilometers.
02:14
So for the magnitude of the resultant, as called this, r, is equal to the square of summation x squared or submission y squared, which is equal to the square of the square of minus the square of.
02:29
454 .7 .9 squared plus 116 .114 squared.
02:39
So this is equal to 469 .0 .4 kilometers...