00:01
Plane traveling with an initial speed of 48 meters per second.
00:05
The altitude they are is 165 meters up in the air, and they're going to drop a package, and we want to know relative to where the plane is at the time, how far over does this package land? this is a horizontal projectile, assuming our plane is flying horizontally.
00:21
And so we have our information in the horizontal and the vertical.
00:26
So this speed is simply in the horizontal.
00:30
At first, and so originally the package has an initial speed in the vertical of zero.
00:35
We're told that acceleration due to gravity is 9 .8.
00:39
It is in the negative direction and only in the vertical.
00:44
This height is also in the vertical, which is 165 meters, and the object will be falling down that distance.
00:50
You need to make sure you put it as negative.
00:52
We are looking for a horizontal distance.
00:55
The only equation in the horizontal you can use, because there is no acceleration, is velocity equals distance over time.
01:01
So we must find time before we can find distance.
01:04
So the first thing we are going to do is use the vertical components, so we use it as green, to solve for our time, because time is the only thing that is the same in both sides.
01:16
And so i'm going to use the equation is displacement.
01:18
It's equal to initial velocity times time plus one -half, acceleration time squared.
01:25
This initial velocity is simply zero, and the displacement is going to be that height.
01:29
So it is negative 165 is equal to 1 1 1 .5 times 9 .8 is negative t squared...