An amount of 6.00 mol of ideal gas doubles its volume at a constant temperature of 200°C? What is the work done by the gas in this process? 8 kJ 53.4 kJ 16.3 kJ 12 kJ
Added by Brian Q.
Step 1
Given: Initial temperature = 200°C To convert to Kelvin, add 273: Initial temperature in Kelvin = 200 + 273 = 473 K Show more…
Show all steps
Your feedback will help us improve your experience
Pritesh Ranjan and 78 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The temperature of 3.00 mol of a gas with Cv = 6.00 cal/mol K is to be raised 50.0 K . If the process is at constant volume, what are the work W done by the gas?
Adi S.
A perfect gas with a mass of 2 kg is expanded to 3 times its initial volume as if balanced PVn = constant. In the meantime, its temperature drops from 300 ° C to 60 ° C. During this process, 20 kJ of heat passes into the environment. The work done is 100 kJ. Calculate the polytropic exponent coefficient and the specific heat of the gas.
When $1210 \mathrm{J}$ of heat are added to one mole of an ideal monatomic gas, its temperature increases from $272 \mathrm{K}$ to $276 \mathrm{K}$. Find the work done by the gas during this process.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD