00:01
In the first part of this question we have given that a diet contains 65 % of alpha -alpha hay, 90 % dm and 35 % corn silage with the 35 % of dm.
00:30
So, in this question we are going to calculate the percentage of alpha -alpha hay and corn silage in a 100 % dm diet.
00:43
So, for this we must convert the percentages of the dry matter basis first in order to get the percentage of alpha -alpha hay and corn silage in a 100 % dm diet.
00:58
So, to use the alpha -alpha hay, 65 % of the diet is made of alpha -alpha hay which has a dm content of 90 % that is 65 % into the 90 % it will become 58 .5%.
01:23
Now, dm regarding the corn silage so which makes up the 35 % of the diet and 35 % of the dm.
01:33
So, that means 35 into 35, 35 % into 35 % which will be equals to 12 .25 % of dm.
01:46
Now, we can multiply the dm percentages to obtain the overall dm percentage that is 12 .25 % more than the 58 .5 % more than more than the 58 .5 % more than the 70 .75%.
02:11
So, we can divide each dm percentage by the overall dm percentage to obtain the percentage for a 100 % dm diet.
02:21
So, it can be 58 .5 % dm into 70 .75 % of dm into 82 .7%.
02:33
So, for silage it can be 12 .25 % dm into 70 .75 % dm which comes 17 .3%.
02:48
So, a diet of 100 % dm must contain 82 .7 % of alpha -alpha hay and 17 .3 % of the corn silage.
03:04
Now, for the next part so in the next we have given a balanced diet of 55 % tdn using a corn chocolate with the 35 % of the tdn and a corn which is 90 % tdn.
03:31
And a diet must contain 20 % of the alpha -alpha hay which is 50 % tdn...