00:01
Hello student, in the given question, in part 1st, we have the probability that an apartment selected at random has 2 bedrooms can be found by adding up the number of apartments with 2 bedrooms and dividing the total number of apartments.
00:17
So the probability that an apartment selected at random has 2 bedrooms, so we have to find this probability as probability of 2 bedrooms is equals to 1 plus 3 plus 4 plus 3 plus 3 plus 6 divided by 3 plus 1 plus 3 plus 5 plus 3 plus 4 plus 2 plus 6 plus 3 which is equals to 23 upon 30 which is equals to 0 .7667.
01:17
So therefore, the probability that an apartment selected at random has 2 bedrooms is approximately equals to 0 .7667.
01:52
Now in 2nd question, we have in 2nd question, the probability that the apartment selected at random has 3 bedrooms, 3 bedrooms or on the 2nd floor can be found by adding up the number of apartment with the 3 bedrooms and the given number of apartments on 2nd floor.
02:18
So probability of 3 bedrooms or 2nd floor can be calculated as which is equals to 3 plus 6 plus 3 upon 3 plus 1 plus 3 plus 5 plus 3 plus 4 plus 2 plus 6 plus 3 which is equals to 15 upon 30 which is equals to 0 .5.
02:47
So therefore, the probability of 3 bedrooms or 2nd floor which is equals to 0 .5.
03:02
Now in the 3rd question, we have to find the probability that an apartment selected at random on the 3rd floor or given that it has 1 bedroom which is equals to probability of 1 bedroom given that 3rd floor multiplied by probability of 3rd floor given that probability of 1 bedroom.
03:50
So we can find the individual probability as follow.
03:58
First, probability of 1 bedroom given 3rd floor is equals to 3 by 3 which is equals to 1 which all apartments on the 3rd floor have 1 bedroom...