00:01
Hi, here this given problem includes so many similar questions.
00:07
So i am solving only the first two.
00:11
In the first one, force applied on the object which is towards right, force applied on the object towards right, that is f is equal to 50 newton and force of friction and countered by the object small f that is 10 newton.
00:59
Fg means gravitational force or weight of the object that is a t newton.
01:12
So if this is the horizontal surface rough surface this is fg weight of the object then the normal force exerted by the surface on the object that will be equal to f g means 80 newton.
01:44
First answer for this problem.
01:49
Then in order to find mass of the object using f g is equal to m into g which is 8 t newton so mass of the object will be 80 by g.
02:11
Here we consider g to be equal to 10 meter per second square here this is 80 newton.
02:23
So the mass here comes out to be equal to 8 kilogram.
02:28
Second answer for this problem.
02:36
Then in the same problem, net force acting on the object that will be equal to applied force minus force of friction.
03:06
This is applied force 50 newton minus force of friction.
03:11
10 newton means this is 40 newton.
03:23
Third answer for the problem.
03:26
Then in order to find coefficient of friction using an expression for the force of friction that is mu times normal reaction.
03:44
So this mu will be given by f by n, 10 by 80...