An aqueous solution is made by dissolving 16.2 grams of lead nitrate in 451 grams of water. The molality of lead nitrate in the solution is
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- Lead (Pb): 207.2 g/mol - Nitrogen (N): 14.01 g/mol - Oxygen (O): 16.00 g/mol The molar mass of Pb(NO3)2 is calculated as follows: - Pb: 207.2 g/mol - N: 2 * 14.01 g/mol = 28.02 g/mol - O: 6 * 16.00 g/mol = 96.00 g/mol Total molar mass of Pb(NO3)2 = 207.2 + Show more…
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