An aqueous solution of an unknown salt of ruthenium is electrolyzed by a current of 2.50 A passing for 50.0 min. If 2.618 g Ru is produced at the cathode, what is the charge on the ruthenium ions in solution?
Added by Daniel T.
Step 1
Given mass of ruthenium = 2.618 g Molar mass of ruthenium = 101.07 g/mol Number of moles of ruthenium = Mass/Molar mass Number of moles of ruthenium = 2.618 g / 101.07 g/mol Number of moles of ruthenium ≈ 0.026 Show more…
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An aqueous solution of an unknown salt of ruthenium is electrolyzed by a current of 2.50 A passing for 50.0 min. If $2.618 \mathrm{g} \mathrm{Ru}$ is produced at the cathode, what is the charge on the ruthenium ions in solution?
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