An aqueous solution of sodium iodide is mixed with an...

An aqueous solution of sodium iodide is mixed with an aqueous solution of mercury(I) acetate. Which of the following statements is TRUE? - a precipitate will be formed - one of the products is mercury(I) iodide - one of the products is sodium acetate but it will remain in the ionized form because it is soluble in water An aqueous solution of potassium sulfate is mixed with an aqueous solution of barium chloride. What precipitate if any will form? - K2SO4 - BaCl2 - KCl - BaSO4 - no precipitate will form - all of the above - none of the above

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00:01 This question wants to know which statements are true when we take a solution of mercury 1 acetate, which is hg2, 2 plus, that's what mercury 1 is, and then acetate is c2, h3, o2, and we'll need two of them.

00:20 According to solubility rules, this is aqueous, and we mix it with sodium myodide, and according to solubility rules, this is aqueous, and we mix it with sodium myodide, and according to solubility rules, this is aqueous.

00:33 When the cations switch places, we will get sodium acetate, which according to the solubility rules is also aqueous, and mercury 1, iodide, which according to solubility rules is insoluble.

00:55 So this is a solid.

00:58 To balance this, we're going to need to put a two here, so we have two acetates.

01:03 That gave us two sodium, so we put a two here.

01:06 That gave us two iodides, and we have two iodide, so it's balanced.

01:12 So the first statement says a precipitate will form.

01:17 That's true.

01:19 A precipitate does form.

01:21 One of the products is mercury iodide.

01:24 Yes, that's actually the precipitate.

01:27 So that one's also true.

01:31 The third statement says one of the products is sodium acetate.

01:36 Yes, that's true.