An aqueous solution was prepared by mixing 42.1 mL of $CH_3OH$ (MM = 32.0) and 91.2 mL of water. Given this information, calculate the $\%v/v$ of $CH_3OH$ present in this solution? Report the answer to 3 significant figures.
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Total volume = Volume of $CH_3OH$ + Volume of water Total volume = 42.1 mL + 91.2 mL = 133.3 mL Show more…
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