An arrow is shot upward, with an initial velocity of 89 meters per second, at an angle of 21° with respect to the horizontal. The arrow is shot from a height of 2 meters above the ground. The horizontal distance x from the starting point and the height y above the ground of the arrow t seconds after it is shot are given by the parametric equations below. x = (v_0 cos ?)t y = -4.9t^2 + (v_0 sin ?)t + h Here v_0 is the initial velocity, ? is the initial angle with respect to the horizontal, and h is the initial height. Use the equations to answer the following questions. (a) How long is the arrow in the air before it first touches the ground? Do not round any intermediate computations. Round your answer to the nearest hundredth. seconds (b) What is the horizontal distance the arrow travels before it first touches the ground? Round your answer to the nearest whole number. meters
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Step 1: To find out how long the arrow stays in the air before it first touches the ground, we need to set the equation for y (height) equal to 0 and solve for t. Show more…
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