Question

An artillery shell is launched on a flat, horizontal field at an angle of αα = 37.1° with respect to the horizontal and with an initial speed of v0 = 276 m/s. What is the horizontal distance covered by the shell after 8.23 s of flight? What is the height of the shell at this moment?

Name: an artillery shell is launched on a flat horizontal field at an angle of 371 with respect to the horizontal and with an initial speed of v0 276 ms what is the horizontal distance covered by 94007
Uploaded: 2021-12-26T11:03:40-08:00
Duration: 1 min 44 s
Channel: Prabhu Ramji
Description: an artillery shell is launched on a flat horizontal field at an angle of 371 with respect to the horizontal and with an initial speed of v0 276 ms what is the horizontal distance covered by 94007

          An artillery shell is launched on a flat, horizontal field at an angle of αα = 37.1° with respect to the horizontal and with an initial speed of v0 = 276 m/s. What is the horizontal distance covered by the shell after 8.23 s of flight? What is the height of the shell at this moment?

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University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Prabhu Ramji

12/26/2021

Step 1

- The horizontal component \( v_{0x} \) is given by: \[ v_{0x} = v_0 \cdot \cos(\alpha) = 276 \cdot \cos(37.1^\circ) \] - The vertical component \( v_{0y} \) is given by: \[ v_{0y} = v_0 \cdot \sin(\alpha) = 276 \cdot \sin(37.1^\circ) \] Show more…

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An artillery shell is launched on a flat, horizontal field at an angle of αα = 37.1° with respect to the horizontal and with an initial speed of v0 = 276 m/s. What is the horizontal distance covered by the shell after 8.23 s of flight? What is the height of the shell at this moment?