An athlete performs a jump with 30° from the ground, which is horizontal, leaving at 12 m/s. The maximum horizontal distance that he can reach, in meters, is: (consider g = 10 m/s2)
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We can use the equation: v = u + at where v is the final velocity (0 m/s at the maximum height), u is the initial velocity (12 m/s), a is the acceleration due to gravity (-10 m/s^2), and t is the time. 0 = 12 - 10t Solving for t, we get: 10t = 12 t = 1.2 s Show more…
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