00:01
Hello everyone, we are going to understand this question here given in the question.
00:10
Value of mass m1, that is 12 kilogram, value of mass m2, that is 19 kilogram, and mass of cylindrical pulley, mass of cylindrical pulley, that is represented by capital m, which is 8 .2 kilogram.
00:44
Radius of pulley that is represented by r which is 0 .2 meter let the acceleration be a let the acceleration be a now applying the reward diagram so here weight of the block is working vertically downward that is m2 into g tension in the issue string that is t 2 net acceleration is in downward direction similarly for the block m1 weight of the block that is m1 into g which is in downward direction tension in the string which is in upward direction and net acceleration is in upward direction so writing the equation force balance equation so here we can write m2 into g minus t2 is equal to m2 into a let this is equation 1.
02:02
Similarly for the first block t1 minus m1 into g is equal to m1 into a this is represented by equation 2 and for the rotating pulley applying the torque equation for pulley we can write t2 minus t 1 into r is equal to i into alpha or we can write t2 minus t1 is equal to i into alpha upon r and moment of inertia of solid cylinder that is m into r square and we know that linear acceleration is m into r square upon two we know that linear acceleration is sorry here moment of inertia of solid cylinder that is mr square upon two this is about the center of the cylinder and linear acceleration is r into alpha so here multiplying and by r so we can write r into alpha upon r square again we can write here r square and r square will get cancelled so it will be m upon 2 into r into alpha is a t2 minus t1 is equal to m into a upon 2 this is equation 3 now from equation 1 2 and 3 now from equation 1 2 and 3 now 3.
03:49
So we can write m2 into g minus m1 into g is equal to m1 plus m2 plus capital m upon 2 into a.
04:06
Now doing further calculations.
04:09
So here we can write a is equal to a is equal to 19 .0 into 9 .8 minus 9.
04:23
19 point sorry here minus 12 .0 into 9 .8 upon 19 plus 12 plus 8 .2 upon 2.
04:47
So after doing further calculation we will get a is equal to after doing further calculation we will get a is equal to after doing further calculation we will get 68 .6 upon 35 .1.
05:18
So after doing further calculation we will get a is equal to 1 .95 meter per second square.
05:31
So the higher mass will apply the higher gravitational force.
05:37
So the higher mass, higher mass will apply the higher gravitational force and the lower mass will apply the lower gravitational force.
06:10
The lower mass will apply the lower gravitational force, lower gravitational force.
06:38
And pulley will start to rotate clockwise...