An object located at r = (3i + 3j - 2k) m has a force F = (5i + 2j) N acting on it. Find the torque about the origin
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Given: r = 5i + 3j - 2k f = 5i + 2j Calculate the cross product: r x f = (3 * 2 - (-2) * 5)i - (5 * 2 - 5 * 5)j + (5 * 3 - 3 * 5)k r x f = (6 + 10)i - (10 - 25)j + (15 - 15)k r x f = 16i + 15j Show more…
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