An electron enters a region of space containing a uniform 1.53 × 10?? T magnetic field. Its speed is 193 m/s and it enters perpendicularly to the field. Under these conditions, the electron undergoes circular motion. Find the radius r of the electron's path and the frequency f of the motion. r = f =
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1 \times 10^{-31} kg\) \(v = 93 m/s\) \(q = 1.60 \times 10^{-19} C\) \(B = 0.53 \times 10^{-3} T\) Substitute the values into the formula: \(r = \frac{9.1 \times 10^{-31} \cdot 93}{1.60 \times 10^{-19} \cdot 0.53 \times 10^{-3}}\) Show more…
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