An earthquake causes a piece of glass to fall off a building from a height of \( 2,704 \mathrm{ft} \). If the equation for height as a function of time is \( h(t)=-16 t^{2}+ \) initial height where \( t \) is time in seconds and \( h(t) \) is height in feet, how many seconds will it take for the piece of glass to hit the ground? [?] seconds
Added by John D.
Close
Step 1
- Initial height = 2,704 ft - Height function: \( h(t) = -16t^2 + \text{initial height} \) Show more…
Show all steps
Your feedback will help us improve your experience
Supreeta N and 71 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A stone is dropped off a 256 -ft cliff. The height of the stone above the ground is given by the equation $h=-16 t^{2}+256$ where $h$ is the stone's height in feet, and $t$ is the time in seconds after the stone is dropped $(t \geq 0)$ Find the time required for the stone to hit the ground.
Factoring Polynomials
Applications of Quadratic Equations
A stone is dropped off a 576-ft cliff. The height of the stone above the ground is given by the equation h = -16t^2 + 576, where h is the stone height in feet and t is the time in seconds after the stone is dropped (t > 0). The time required for the stone to hit the ground is (blank) seconds.
Victor S.
Nishant K.
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD