An elastic aluminum rod (E = 70 GPa) is 4 m long w/ a cross-sectional area of 7.5 cm^2. The rod carries an axial tensile load of 150 kN. Calculate the elongation of the rod.
Added by Salvador C.
Step 1
Stress is defined as the force applied per unit area. In this case, the force is 150 kN and the cross-sectional area is 7.5 cm^2. Stress = Force / Area Converting the force to Newtons: 150 kN = 150,000 N Converting the area to square meters: 7.5 cm^2 = 7.5 * Show more…
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