An electrical current-carrying conductor forms part of the rotating armature of an elecrtic motor. It is parallel to the axis of rotation and 235 mm from it. A constant magnetic field is caused to pass over it, thus generating a tenagential force, F = 11.8 N. If the armature has a moment of inertia of I = 0.21 kgm² and is not driving any connected load, what angular acceleration (caused by the conductor acting alone) would be experienced by the armature?
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The torque (τ) acting on the armature can be calculated using the formula τ = F * r, where F is the tangential force and r is the distance from the axis of rotation. In this case, F = 11.8 N and r = 235 mm = 0.235 m. Therefore, τ = 11.8 N * 0.235 m = 2.773 Nm. Show more…
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