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An electromagnetic rail gun can fire a projectile using a magnetic field and an electric current. Consider two conducting rails that are $0.500 \mathrm{~m}$ apart with a $50.0-\mathrm{g}$ conducting rod connecting the two rails as in the figure with Problem $39 .$ A magnetic field of magnitude $0.750 \mathrm{~T}$ is directed perpendicular to the plane of the rails and rod. A current of $2.00$ A passes through the rod. (a) What direction is the force on the rod? (b) If there is no friction between the rails and the rod, how fast is the rod moving after it has traveled $8.00 \mathrm{~m}$ down the rails?

          An electromagnetic rail gun can fire a projectile using a magnetic field and an electric current. Consider two conducting rails that are $0.500 \mathrm{~m}$ apart with a $50.0-\mathrm{g}$ conducting rod connecting the two rails as in the figure with Problem $39 .$ A magnetic field of magnitude $0.750 \mathrm{~T}$ is directed perpendicular to the plane of the rails and rod. A current of $2.00$ A passes through the rod. (a) What direction is the force on the rod? (b) If there is no friction between the rails and the rod, how fast is the rod moving after it has traveled $8.00 \mathrm{~m}$ down the rails?
        
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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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An electromagnetic rail gun can fire a projectile using a magnetic field and an electric current. Consider two conducting rails that are $0.500 \mathrm{~m}$ apart with a $50.0-\mathrm{g}$ conducting rod connecting the two rails as in the figure with Problem $39 .$ A magnetic field of magnitude $0.750 \mathrm{~T}$ is directed perpendicular to the plane of the rails and rod. A current of $2.00$ A passes through the rod. (a) What direction is the force on the rod? (b) If there is no friction between the rails and the rod, how fast is the rod moving after it has traveled $8.00 \mathrm{~m}$ down the rails?
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Transcript

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00:01 All right, so let's say we have a rail gun that has two rails that are a distance of half a meter apart.
00:08 And we have a rail that has a mass of 50 grams.
00:17 It's 0 .05 kilograms.
00:19 And it's subjected to a magnetic field that is perpendicular to the plane of the rod.
00:25 So this is b, we'll call this 0 .75 tesla.
00:29 And we're told a current of two amps passes through the rod.
00:34 What direction is the force on the rod? so the force is going to be the magnetic field times the current, times the length of the rod.
00:41 So 0 .75 tesla times two amps times...
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