Given that $\vec{E} = (960 \text{ N/C})\hat{j}$, the magnitude of the electric field is $E = 960 \text{ N/C}$.
We can find the magnitude of the magnetic field:
$B = \frac{E}{c} = \frac{960 \text{ N/C}}{3 \times 10^8 \text{ m/s}} = 3.2 \times 10^{-6} \text{
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