"An electron, after being accelerated through a potential difference of 10^4 V, enter a uniform magnetic field of 0.04 T, perpendicular to its direction of motion. Calculate the radius of curvature of its trajectory"
Added by Shirlin S.
Step 1
The kinetic energy (KE) gained by the electron is equal to the work done on it by the electric field, which is given by the equation: \[ KE = eV \] where \( e \) is the charge of the electron (\( e = 1.6 \times 10^{-19} \, \text{C} \)) and \( V \) is the potential Show more…
Show all steps
Close
Your feedback will help us improve your experience
Dinesh Chand Jangid and 87 other Intro Stats / AP Statistics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
An electron is accelerated from rest through a potential difference of $3750 \mathrm{~V}$. It enters a region where $B=4.0 \times 10^{-3} \mathrm{~T}$ perpendicular to its velocity. Calculate the radius of the path it will follow.
An electron is accelerated from rest through a potential difference of 3750 V. It enters a region where the magnetic field is 4.0 mT perpendicular to the velocity of the electron. Calculate the radius of the path this electron will follow.
Suman K.
An electron is accelerated from rest by a potential difference of 450 V. It then enters a uniform magnetic field of magnitude 280 mT with its velocity perpendicular to the field. Calculate the speed of the electron. Calculate the radius of its path in the magnetic field.
Brian F.
Recommended Textbooks
Elementary Statistics a Step by Step Approach
The Practice of Statistics for AP
Introductory Statistics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD