Question

An electron enters the region of a uniform electric field as shown in figure, with v_i = 5.00 × 10^6 m/s and E = 200 N/C. The horizontal length of the plates is l = 0.200 m. If the vertical position of the electron as it enters the field is y_i = 0, what is its vertical position when it leaves the field? (Hint: First find the acceleration, then the time and finally using kinematics equation find the vertical position of the electron) (q_e = -1.6 × 10^-19C, m_e = 9.11 × 10^-31kg) a. -4.28 cm b. -2.808 cm c. -1.95 cm d. -0.57 cm e. -5.05 cm 

          An electron enters the region of a uniform electric field as shown in figure, with v_i = 5.00 × 10^6 m/s and E = 200 N/C. The horizontal length of the plates is l = 0.200 m. If the vertical position of the electron as it enters the field is y_i = 0, what is its vertical position when it leaves the field? (Hint: First find the acceleration, then the time and finally using kinematics equation find the vertical position of the electron) (q_e = -1.6 × 10^-19C, m_e = 9.11 × 10^-31kg)

a. -4.28 cm
b. -2.808 cm
c. -1.95 cm
d. -0.57 cm
e. -5.05 cm
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An electron enters the region of a uniform electric field as shown in figure, with vi = 5.00 #215; 10^6 m/s and E = 200 N/C. The horizontal length of the plates is l = 0.200 m. If the vertical position of the electron as it enters the field is yi = 0, what is its vertical position when it leaves the field? (Hint: First find the acceleration, then the time and finally using kinematics equation find the vertical position of the electron) (qe = -1.6 #215; 10^-19C, me = 9.11 #215; 10^-31kg) a. -4.28 cm b. -2.808 cm c. -1.95 cm d. -0.57 cm e. -5.05 cm

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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An electron enters the region of a uniform electric field as shown in figure, with vi = 5.00 × 10^6 m/s and E = 200 N/C. The horizontal length of the plates is l = 0.200 m. If the vertical position of the electron as it enters the field is yi = 0, what is its vertical position when it leaves the field? (Hint: First find the acceleration, then the time and finally using kinematics equation find the vertical position of the electron) (qe = -1.6 × 10^-19C, me = 9.11 × 10^-31kg) a. -4.28 cm b. -2.808 cm c. -1.95 cm d. -0.57 cm e. -5.05 cm
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Transcript

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00:01 Š”Š°Ń€Š°Š¼, тут mēs tevam nevajagt y -dizplizmatu.
00:03 LaiŔu to.
00:04 Y -dizplizmatu kā akcelerācija times square time divadu pa 2, un time laiŔu divadu pa time of the flight, pa speed v -initial.
00:22 Nē, laiÅ”u nevajagt.
00:40 Nē, laiÅ”u nevajagt akcelerāciju, tāpēc elektrÄ«ka forca over mass, un Å”op sometimes it is and now you can calculate y...
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