an electron in cathode ray tube is accelerated through potential difference of 10 kv then passes

Step 1: Calculate the velocity of the electron using the formula (v = sqrt{frac{2qDelta V}{m

An electron in cathode ray tube is accelerated through...

An electron in a cathode-ray tube is accelerated through a potential difference of 10 kV, then passes through the d = 20 cm wide region of a uniform magnetic field in the figure (Figure 1). What field strength will deflect the electron by θ = 11°? Express your answer to two significant figures and include the appropriate units. B = 0.0883 T

Transcript

00:01 High given the value of the potential difference v is equal to 10 kilo volts and the value of the distance d is equal to 2 .0 centimeter.

00:13 We need to find the field strength when the electron deflects by an angle theta is equal to 11 degree.

00:20 So when an electron travels in the presence of magnetic field, then the force due to the magnetic field fb is equal to the centripetal 4 .5 .5.

00:31 Force which makes the electron traverse in the circular path.

00:35 So if we write down the expressions, we have bqb is equal to mv squared divided by r.

00:43 So this is the force due to magnetic field and this is the force due to the centripetal force.

00:49 So after rearranging the terms by canceling the velocities on both sides, we get the expression for velocity v is equal to root over 2 q into delta v so here we supposed the potential to be delta v divided by m so here we have taken that the value of the kinetic energy is equal to potential energy in such cases we get half mv square is equal to q into delta v so this delta v is so this delta v is supposed to be the potential difference and this small we represents the velocity.

01:32 From these expression we got this value.

01:34 Velocity is equal to 2 q delta v by m.

01:37 Now we are going to substitute the values here and find out the velocity.

01:43 So velocity of the electron will be root over the 2 into charge of the electron is 1 .6 into 10 power minus 19 coulumes multiplied by the potential is 10 into 10 power 3 divided by the mass of electron is 9 .1 into 10 power minus 31...

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