Question

An electron is accelerated by a constant electric field of magnitude 300 $\mathrm{N} / \mathrm{C}$ . (a) Find the acceleration of the electron. (b) Use the equations of motion with constant acceleration to find the electron's speed after $1.00 \times 10^{-4} \mathrm{s}$ , assuming it starts from rest.

Name: An electron is accelerated by a constant electric field of magnitude 300 N / C . (a) Find the acceleration of the electron. (b) Use the equations of motion with constant acceleration to find the electron's speed after 1.00 × 10^-4s , assuming it starts from rest.
Uploaded: 2021-12-01T09:05:14-08:00
Duration: 1 min 56 s
Channel: Prabhu Ramji
Description: An electron is accelerated by a constant electric field of magnitude 300 N / C . (a) Find the acceleration of the electron. (b) Use the equations of motion with constant acceleration to find the electron's speed after 1.00 × 10^-4s , assuming it starts from rest.

          An electron is accelerated by a constant electric field of magnitude 300 $\mathrm{N} / \mathrm{C}$ . (a) Find the acceleration of the electron. (b) Use the equations of motion with constant acceleration to find the electron's speed after $1.00 \times 10^{-4} \mathrm{s}$ , assuming it starts from rest.

Added by Miguel A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Prabhu Ramji

12/01/2021

Step 1

Given: Electric field magnitude, $E = 300 \, \mathrm{N/C}$ Charge of electron, $q = 1.6 \times 10^{-19} \, \mathrm{C}$ Mass of electron, $m = 9.11 \times 10^{-31} \, \mathrm{kg}$ The acceleration of the electron can be calculated using the formula: \[ a = \frac{q Show more…

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An electron is accelerated by a constant electric field of magnitude 300 $\mathrm{N} / \mathrm{C}$ . (a) Find the acceleration of the electron. (b) Use the equations of motion with constant acceleration to find the electron's speed after $1.00 \times 10^{-4} \mathrm{s}$ , assuming it starts from rest.