Question

An electron is accelerated from rest through a potential difference that has a magnitude of $2.40 \times 10^7$ V. The mass of the electron is $9.11 \times 10^{-31}$ kg, and the negative charge of the electron has a magnitude of $1.60 \times 10^{-19}$ C. (a) What is the relativistic kinetic energy (in joules) of the electron? (b) What is the speed of the electron? Express your answer as a multiple of $c$, the speed of light in a vacuum.

Name: An electron is accelerated from rest through a potential difference that has a magnitude of 2.40 × 10^7 V. The mass of the electron is 9.11 × 10^-31 kg, and the negative charge of the electron has a magnitude of 1.60 × 10^-19 C. (a) What is the relativistic kinetic energy (in joules) of the electron? (b) What is the speed of the electron? Express your answer as a multiple of c, the speed of light in a vacuum.
Uploaded: 2021-03-08T18:11:40-08:00
Duration: 2 min 17 s
Channel: Narayan Hari

          An electron is accelerated from rest through a potential difference that has a magnitude of $2.40 \times 10^7$ V. The mass of the electron is $9.11 \times 10^{-31}$ kg, and the negative charge of the electron has a magnitude of $1.60 \times 10^{-19}$ C. (a) What is the relativistic kinetic energy (in joules) of the electron? (b) What is the speed of the electron? Express your answer as a multiple of $c$, the speed of light in a vacuum.

An electron is accelerated from rest through a potential difference that has a magnitude of 2.40 × 10^7 V. The mass of the electron is 9.11 × 10^-31 kg, and the negative charge of the electron has a magnitude of 1.60 × 10^-19 C. (a) What is the relativistic kinetic energy (in joules) of the electron? (b) What is the speed of the electron? Express your answer as a multiple of c, the speed of light in a vacuum.

Added by Alba M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Narayan Hari

03/08/2021

Step 1

The electric potential energy (PE) of an electron accelerated through a potential difference (V) is given by the equation: PE = qV where q is the charge of the electron. The charge of an electron is -1.6 x 10^-19 C. PE = (-1.6 x 10^-19 C)(2.40 x 10^7 V) Show more…

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An electron is accelerated from rest through a potential difference that has a magnitude of 2.40 x 107 V. The mass of the electron is 9.11 10-31 kg, and the negative charge of (in joules) of the electron? (b) What is the speed of the electron? Express your answer as a multiple of c, the speed of light in a vacuum. (a) Number i Units (b) Number i Units