00:01
In this problem we have been given that there is an electron and it's moving at a speed of 8 times 10 raise to 6 meter per second.
00:11
So this electron is having same d -proglese wavelength as compared to that of the proton.
00:18
So here we can see that the wavelength of electron is equal to the wavelength of proton provided that we're talking about the d -procles wavelength.
00:26
So we know that according to d -progles hypothesis the wave nature is inversely proportional to the particle nature.
00:34
And from here we get an expression out of this, that's lambda is equal to edge by p.
00:39
H here is the plank's constant.
00:41
P here is the momentum, which can be written as m times v.
00:47
That's the mass times the velocity.
00:49
So we can observe that in the case of electrons, its wave length will be equal to h by mass of electrons times the speed of electron, that's 8 times 10 raise to 6.
01:00
And this will be equal to the wavelength of the proton, that's equal to the planks constant divided by the mass of proton times the speed of proton.
01:12
And from here we can say that we get an equation, m .e.
01:16
Into 8 into 10 raise to 6...