An electron is placed in a uniform electric field of strength 232 N/C directed in the negative x direction. If the electron is at rest at x = 0 and at t = 0, what is the position of the electron at t = 1.30 ns?
Added by Rebecca E.
Step 1
Given: \(Q = 1.6 \times 10^{-19} C\) \(E = 232 N/C\) \(m = 9.1 \times 10^{-31} kg\) Calculate: \(a = \frac{1.6 \times 10^{-19} \cdot 232}{9.1 \times 10^{-31}} = 4.08 \times 10^{13} m/s^2\) Show more…
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