An electron is placed in an electric field and allowed to accelerate to a distance of 1 m. If the electric field strength is E = 200 V / m, what is the final velocity of the electron, assuming it starts from rest?
Added by April F.
Step 1
Given: Charge of electron, q = -1.6 x 10^-19 C Electric field strength, E = 200 V/m Electric force, F = qE F = -1.6 x 10^-19 C * 200 V/m F = -3.2 x 10^-17 N Show more…
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