Question

An electron moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 2.0 mT. If the velocity of the electron is 1.5x10^7 m/s, determine (a) the radius of the circular path and (b) the time it takes to complete one revolution. a. 5.4 cm; 1.5x10^8 s b. 4.3 cm; 1.8x10^-8 s c. 78 m; 3.2x10^5 s d. 4 m; 6.2x10^7 s

Name: an electron moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 20 mt if the velocity of the electron is 15x107 m s determine a the radius of the circular 86194
Uploaded: 2022-02-26T06:16:07-08:00
Duration: 2 min 2 s
Channel: Kajal Raghubanshi
Description: an electron moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 20 mt if the velocity of the electron is 15x107 m s determine a the radius of the circular 86194

          An electron moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 2.0 mT. If the velocity of the electron is 1.5x10^7 m/s, determine (a) the radius of the circular path and (b) the time it takes to complete one revolution.
a. 5.4 cm; 1.5x10^8 s
b. 4.3 cm; 1.8x10^-8 s
c. 78 m; 3.2x10^5 s
d. 4 m; 6.2x10^7 s

Added by Andrea J.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Kajal Raghubanshi

02/26/2022

Step 1

Given: Mass of electron, \(m = 9.1 \times 10^{-31} kg\) Velocity of electron, \(v = 1.5 \times 10^7 m/s\) Charge of electron, \(q = 1.6 \times 10^{-19} C\) Magnetic field, \(B = 2.0 \times 10^{-3} T\) Plugging in the values: \(r = \frac{(9.1 \times 10^{-31} kg) Show more…

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An electron moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 2.0 mT. If the velocity of the electron is 1.5x10^7 m/s, determine (a) the radius of the circular path and (b) the time it takes to complete one revolution. a. 5.4 cm; 1.5x10^8 s b. 4.3 cm; 1.8x10^-8 s c. 78 m; 3.2x10^5 s d. 4 m; 6.2x10^7 s