An electron moving with a velocity of 26 m/s enters region A with a uniform electric field of 13 V/m that is directed opposite to the direction of motion of the electron (so the electric force is in the direction of motion). The electron travels a distance of 3 nm before exiting the region A. The velocity of the electron when it exits this region is m/s. Take the mass of the electron to be 9.1x10^(-31) kg and its charge to be 1.6x10^(-19) C.
(b)
The electron now enters region B with a uniform magnetic field of 8 mT perpendicular to its direction of motion. The radius of the circular path the electron would follow in this region is nm.