Question

An electron moving with a velocity of 5 x 104 m/s enters into a uniform electric field and acquires a uniform acceleration of 104m/s2 in the direction of its initial motion. (i) Calculate the time in which the electron would acquire a velocity double of its initial velocity. (ii) How much distance the electron would cover in this time?

Name: an electron moving with a velocity of 5 x 104 ms enters into a uniform electric field and acquires a uniform acceleration of 104ms2 in the direction of its initial motion i calculate the time in which
Uploaded: 2022-04-02T14:56:57-08:00
Duration: 4 min 47 s
Channel: Jaya M
Description: an electron moving with a velocity of 5 x 104 ms enters into a uniform electric field and acquires a uniform acceleration of 104ms2 in the direction of its initial motion i calculate the time in which

          An electron moving with a velocity of 5 x 104 m/s enters into a uniform electric field and acquires a uniform acceleration of 104m/s2 in the direction of its initial motion. (i) Calculate the time in which the electron would acquire a velocity double of its initial velocity. (ii) How much distance the electron would cover in this time?

Added by Nate S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Jaya M

04/02/2022

Step 1

- The initial velocity of the electron, \(u\), is \(5 \times 10^4\) m/s. - The acceleration, \(a\), is \(10^4\) m/s\(^2\). - The final velocity we are looking for is double the initial velocity, so \(v = 2u = 2 \times 5 \times 10^4 = 10^5\) m/s. Show more…

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An electron moving with a velocity of 5 x 104 m/s enters into a uniform electric field and acquires a uniform acceleration of 104m/s2 in the direction of its initial motion. (i) Calculate the time in which the electron would acquire a velocity double of its initial velocity. (ii) How much distance the electron would cover in this time?