An electron q e m 911 x 1031 kg is released from rest next...

An electron (q = –e, m = 9.11 x 10^–31 kg) is released from rest next to the negatively charged electrode of a parallel plate capacitor. The capacitor plates are separated by 2 mm, have a diameter of 4 cm, and are charged to ±50 nC. a) What is the strength of the electric field inside the capacitor? b) What is the acceleration of the electron after it is released? (*Hint: What force acts on the electron?) c) What is the electron’s speed just before it hits the positively charged electrode?

Transcript

00:01 This question we are given here electron is released from the rest next to negative charge electrode and parallel we are given here electrode or parallel plate capacitor so we are given here parallel plate capacitor parallel plate capacitor and the capacity is separated by 2 millimeter so distance we are given here is 2 millimeter we just converted in a meter so we can write 2 multiple 10 minus 3 meter and have a diameter we are given here so d which is equal to here we just separate your diameter denoted by d prime so diameter is 4 cm so we can write 4 multiply by 10 x to minus 2 meter now our charge we are given here so we can write q which is equal to pros of minus 50 nanocolum so we can write 50 plus or minus 50 multiply by we can write here 10 to minus 9 column here the first part of this question a we want to find the strength of the electric field inside the capacitor so here we want to find the strength of electric field inside the capacitor so how to find the strength of the electric field so we know the formula of e which is equal to q divided by by epsilon in or multiple by a so we can write here here e which is equal to we just substitute value into this formula so you can write value of 50 charge 50 multiple by 10 to minus 9 column divided by we can write here value of tsunami node is we can write 8 .85 multiple by 10 to minus 12 multiple we can write here a value of pi so we can write pi divided by 4 and here we know that value of the diameter diameter is 4 centimeters so you can write here 4 multiply by 10 x to minus 2 that is the value we are given here 4 multiple 5 multiple of 10 minus 2 square now we just simplify all this value and here we can write here the electric field which is equal to answer here is 4 .50 multiple blah we can write here 10 to 6 that is newton per column so this is the value of electric field so this is the value of electric field now let's solve second subpart of this question to be so in the way we can write that is in the b we want to find what is the acceleration…

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