Question

An electron that is moving through a uniform magnetic field has a velocity v = (50 km/s)i + (40 km/s)j when it experiences a force F = (-3.600×10-15 N)i + (4.500×10-15 N)j due to the magnetic field. If Bx = 0, calculate the magnitude of the magnetic field B. (Tesla = T) What is By? What is Bz?

Name: an electron that is moving through a uniform magnetic field has a velocity v 50 kmsi 40 kmsj when it experiences a force f 360010 15 ni 450010 15 nj due to the magnetic field if bx 0 calcula 14242
Uploaded: 2022-06-20T12:20:47-08:00
Duration: 4 min 13 s
Channel: Khoobchandra Agrawal
Description: an electron that is moving through a uniform magnetic field has a velocity v 50 kmsi 40 kmsj when it experiences a force f 360010 15 ni 450010 15 nj due to the magnetic field if bx 0 calcula 14242

          An electron that is moving through a uniform magnetic field has a velocity v = (50 km/s)i + (40 km/s)j when it experiences a force F = (-3.600×10-15 N)i + (4.500×10-15 N)j due to the magnetic field. If Bx = 0, calculate the magnitude of the magnetic field B. (Tesla = T)
What is By?
What is Bz?

Added by Kurt T.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Khoobchandra Agrawal

06/20/2022

Step 1

Given: Force F = (-3.600×10^-15 N)i + (4.500×10^-15 N)j Charge of electron q = -1.6×10^-19 C Velocity v = (50 km/s)i + (40 km/s)j Using the formula F = q(v x B), we can equate the x-components: -3.600×10^-15 = -1.6×10^-19(40Bz) Solving for Bz: Bz = 9×10^-14 T Show more…

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An electron that is moving through a uniform magnetic field has a velocity v = (50 km/s)i + (40 km/s)j when it experiences a force F = (-3.600×10-15 N)i + (4.500×10-15 N)j due to the magnetic field. If Bx = 0, calculate the magnitude of the magnetic field B. (Tesla = T) What is By? What is Bz?