Question

An electron is traveling at a velocity of 65 m/s horizontally to the west in a vertically upward magnetic field of strength 0.75 T. Calculate the magnitude and direction of the force on the electron.

Name: an electron traveling 65ms horizontally to the west in a vertically upward magnetic field of strength 075 t calculate the magnitude and direction of the force on the electron 37707
Uploaded: 2022-05-26T13:57:58-08:00
Duration: 1 min 29 s
Channel: Khoobchandra Agrawal
Description: an electron traveling 65ms horizontally to the west in a vertically upward magnetic field of strength 075 t calculate the magnitude and direction of the force on the electron 37707

          An electron is traveling at a velocity of 65 m/s horizontally to the west in a vertically upward magnetic field of strength 0.75 T. Calculate the magnitude and direction of the force on the electron.

Added by Kelly A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Khoobchandra Agrawal

05/26/2022

Step 1

- The velocity of the electron, \(v = 65 \, \text{m/s}\), is directed horizontally to the west. - The magnetic field strength, \(B = 0.75 \, \text{T}\), is directed vertically upward. - The charge of an electron, \(q = -1.6 \times 10^{-19} \, \text{C}\). Show more…

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An electron is traveling at a velocity of 65 m/s horizontally to the west in a vertically upward magnetic field of strength 0.75 T. Calculate the magnitude and direction of the force on the electron.