00:03
Hi there.
00:04
This question is a dilution problem.
00:07
In a dilution problem, we start with a stock solution of a certain concentration, and we attempt to make a solution that is of a lesser concentration.
00:18
And we do that by adding more solvent to it.
00:21
We dilute it.
00:23
So the equation that we use for a dilution problem is m1 times v1 equals m2 times v2, where m is molarity, viz volume, the one is represent the initial or the stock solution, and the twos represent the diluted solution.
00:40
So in this problem, our stock solution has a molarity of 10 .5 molar.
00:46
And we want to know what volume of that we need to use if we're going to make a solution that has a concentration of 2 .5 molar and has a volume of 150 milliliters.
01:02
Okay, so we have an algebraic problem here where we need to solve for v1.
01:06
To do that, we're going to divide both sides by the 10 .5 molar...