Question

An engine valve spring having 12 coils has the ends squared and ground. The outside diameter of the coil is 110 mm and the wire diameter is 11 mm. It has a free length of 180 mm. A. Determine the length of the wire to which this spring must be initially compressed to hold a bolt pressure of 1.01 MPa on the valve seat of 4 cm diameter. Modulus of rigidity is taken as G = GN/m². (A) 100 mm (B) 98.5 mm (C) 97.9 mm (D) 96 mm B. Find the spring stress if it is compressed to its solid length. (A) 160 MPa (B) 165.5 MPa (C) 168.2 MPa (D) 163.3 MPa

          An engine valve spring having 12 coils has the ends squared and ground. The outside diameter of the coil is 110 mm and the wire diameter is 11 mm. It has a free length of 180 mm.

A. Determine the length of the wire to which this spring must be initially compressed to hold a bolt pressure of 1.01 MPa on the valve seat of 4 cm diameter. Modulus of rigidity is taken as G = GN/m².

(A) 100 mm
(B) 98.5 mm
(C) 97.9 mm
(D) 96 mm

B. Find the spring stress if it is compressed to its solid length.

(A) 160 MPa
(B) 165.5 MPa
(C) 168.2 MPa
(D) 163.3 MPa
        
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Added by Ismael V.

University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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An engine valve spring having 12 coils has the ends squared and ground. The outside diameter of the coil is 110 mm and the wire diameter is 11 mm. It has a free length of 180 mm. A. Determine the length of the wire to which this spring must be initially compressed to hold a bolt pressure of 1.01 MPa on the valve seat of 4 cm diameter. Modulus of rigidity is taken as G = GN/m². (A) 100 mm (B) 98.5 mm (C) 97.9 mm (D) 96 mm B. Find the spring stress if it is compressed to its solid length. (A) 160 MPa (B) 165.5 MPa (C) 168.2 MPa (D) 163.3 MPa
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Transcript

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00:01 Force exerted by outer spring force exerted by outer spring is f1 is equals to delta 1 plus g d1 raised to power 4 divided by 8 d1 cube multiplied by n1 where d1 is wire diameter of outer spring which is 3 mm n1 is number of coils of the outer spring which is 12 and d1 is mean diameter so that putting the values we will get f1 will be equals to 0 .015 plus kt multiplied by 10 raised to power 9 multiplied by 0 .003 raised to power 4 divided by 8 multiplied by 0…
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