Question

An enzyme has a K$_M$ of 47 µM. If the V$_{max}$ of the preparation is 22 µmol$\cdot$L$^{-1}\cdot$min$^{-1}$, what velocity would be observed in the presence of 6 µM substrate and 5 µM of an uncompetitive inhibitor that has a K$_I$ of 3 µM.

          An enzyme has a K$_M$ of 47 µM. If the V$_{max}$ of
the preparation is 22 µmol$\cdot$L$^{-1}\cdot$min$^{-1}$, what
velocity would be observed in the presence
of 6 µM substrate and 5 µM of an
uncompetitive inhibitor that has a K$_I$ of 3
µM.

An enzyme has a KM of 47 µM. If the Vmax of
the preparation is 22 µmol·L^-1·min^-1, what
velocity would be observed in the presence
of 6 µM substrate and 5 µM of an
uncompetitive inhibitor that has a KI of 3
µM.

Added by Jose Ignacio H.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Derrick Danso

10/18/2022

Step 1

Step 1: Write down the Michaelis-Menten equation for uncompetitive inhibition: $v = \frac{V_{max}[S]}{K_M[S] + \alpha'[S]}$ where $\alpha' = 1 + \frac{[I]}{K_i}$ Show more…

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An enzyme has a $K_M$ of 47 µM. If the $V_{max}$ of the preparation is 22 µmol·L$^{-1}$·min$^{-1}$, what velocity would be observed in the presence of 6 µM substrate and 5 µM of an uncompetitive inhibitor that has a $K_i$ of 3 µM.