An ice dancer with her arms stretched out starts into a spin with an angular velocity of 1.00 rad/s. Her moment of inertia with her arms stretched out is 2.48 kg m2. What is her angular velocity when she pulls in her arms to make her moment of inertia 1.40 kg m2?
Added by Cody S.
Step 1
This means that the product of her moment of inertia and her angular velocity before she pulls in her arms is equal to the product of her moment of inertia and her angular velocity after she pulls in her arms. Mathematically, this can be expressed as: I1 * ω1 = Show more…
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An ice dancer with her arms stretched out starts into a spin with an angular velocity of 1.00 rad/s. Her moment of inertia with her arms stretched out is 2.48 kg m^2. What is her angular velocity when she pulls in her arms to make her moment of inertia 1.40 kg m^2? A. 0.56 rad/s B. 1.40 rad/s C. 1.77 rad/s D. 1.90 rad/s E. 3.47 rad/s
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