0:00
Hi.
00:01
Here in this given problem mass of the ice hockey player that is m1 is equal to 93 .5 kilogram and mass of hockey puck that is given as 0 .14 kilogram.
00:37
Speed given to the puck hockey puck that is v2 is equal to 309.
00:54
0 .5 meter per second.
00:58
In the first part of the problem, distance of the goal for that hockey puck that is given as d.
01:13
So time taken by the puck to reach to the goal that will be given by t1 or as the time will be same for the hockey puck and the player so we take it to be t only so that time will be given by time equals to distance upon speed, speed of the hockey puck v2.
01:52
Now using conservation of linear momentum, initial momentum of both the player and the hockey puck, that was 0 because both of them were at rest.
02:07
So using conservation of linear momentum, initial momentum 0, that is equal to final momentum m1, v1, linear momentum of the hockey player plus m1.
02:26
To v2, linear momentum of the puck, hockey puck.
02:31
So this v2, sorry, v1, speed achieved by the player, that will be given by minus m2 into v2 divided by m1.
02:48
Or in magnitude only, that is m2, v2 divided by m1...